NU=0.023Re0.8 Pr0.4 (1)
where
Nusselt
number NU=hd/12k
Reynolds
number Re=15.2Wd/m
Prandtl
number Pr=mCp/k
h=tube
side heat transfer coefficient,Btu/ft2hF
d=tube
inner diameter,in
W=flow
rate per tube,lb/h
k=thermal
conductivity,Btu/fthF
Cp=specific
heat,Btu/lbF
m=viscosity,lb/fth
The
fluid properties are estimated at the average fluid temperature
Substituting
the above expressions into the equation (1) and simplifying we have:
h = 2.44W0.8 C/d1.8
where C=(Cp/m)0.4k0.6
Computation
of C requires reference to fluid properties and hence can be tedious.C
has been computed by the author for various fluids and for good engineering
estimates,the equations/data shown below may be used.
C
values for Saturated,Superheated steam
pressure,psia | 100 | 500 | 1000 | 2000 |
sat steam | 0.244 | 0.417 | 0.490 | 0.900 |
400 F | 0.271 | |||
500 | 0.273 | 0.360 | ||
600 | 0.281 | 0.322 | 0.413 | |
700 | 0.291 | 0.316 | 0.358 | 0.520 |
800 | 0.305 | 0.320 | 0.345 | 0.420 |
900 | 0.317 | 0.327 | 0.347 | 0.394 |
1000 F | 0.325 | 0.340 | 0.353 | 0.386 |
Example:
Determine the tube side heat transfer coefficient when 5000 lb/h of superheated
steam at 1000 psia and 800 F flows inside a superheater tube of inner diameter
1.75 in.
Solution:
C =0.345
h
=2.44 x50000.8x0.345/1.751.8 = 271 Btu/ft2hF
C
values for air,flue gases at atmospheric pressure
temp,F | 200 | 400 | 600 | 800 | 1000 | 1200 |
C | 0.162 | 0.172 | 0.180 | 0.187 | 0.194 | 0.205 |
Table: data of gas properties
gas | % volume | Cp | m | k | MW |
N2 | 80 | 0.286 | 0.108 | 0.03 | 28 |
O2 | 12 | 0.270 | 0.125 | 0.043 | 32 |
SO2 | 8 | 0.210 | 0.105 | 0.040 | 64 |
Solution:
Cpm
=0.286x0.8x28+0.27x0.12x32+0.21x0.08x64/(0.8x28+0.12x32+0.08x64) =0.272
Btu/lbF
mm
= 0.108x280.5x0.8+0.125x320.5x0.12+0.105x640.5x0.08/(0.8x280.5+0.12x320.5+0.08x640.5)=0.109
lb/fth
km
= 0.03x280.33x0.8+0.043x320.33x0.12+0.04x640.33x0.08/(0.8x280.33+0.12x320.33+0.08x640.33)=0.032
Btu/fthF
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